2al(s)+fe2o3(s)−→−heatal2o3(s)+2fe( l) 2al(s)+fe2o3(s)→heatal2o3(s)+2fe(l) if 26.1 kg al26.1 kg al reacts with an excess of fe2o3,fe2o3, how many kilograms of al2o3al2o3 will be produced?

Answer : The mass of produced will be, 49.32 Kg

Explanation : Given,

Mass of = 26.1 Kg  = 26100 g

Molar mass of = 26.98 g/mole

Molar mass of = 32 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of .

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of react to give 1 mole of

So, 967.38 moles of react to give moles of

Now we have to calculate the mass of .

Therefore, the mass of produced will be, 49.32 Kg