No3 + 12 + 103 + no2
what is being oxidized?

NO₃⁻ is reduced; I₂ is oxidized

Explanation:

I think your equation is supposed to be

NO₃⁻ + I₂ ⟶ IO₃⁻ + NO₂

If you break the equation into two half-reactions, you get

NO₃⁻ + 2H⁺ + e⁻ ⟶ NO₂ + H₂O

I₂ + 3H₂O ⟶ IO₃⁻ + 6H⁺ + 5e⁻

We see that NO₃⁻ gains an electron, so it is reduced.

I₂ loses five electrons, so it is oxidized.

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.