Limestone (caco3) is decomposed by heating to quicklime (cao) and carbon dioxide. calculate how many grams of quicklime can be produced from 5.0 kg of limestone.

A decomposition reaction splits the reactants into two or more products. The mass of the quicklime produced from 5 kg of limestone is 2800 gm.

Mass is the amount or the weight of the substance occupied in the system. It can be calculated in grams or kilograms.

The decomposition reaction of the Limestone can be shown as:

The number of the mole of limestone is given as:

Here, mass is 5000 gm and the molar mass is 100 g/mol

Substituting values in the equation above:

The stoichiometry coefficient of the reaction gives:

1 mole of limestone = 1 mole quicklime

So, 50 moles of limestone = x moles of quicklime

Solving for x:

Mass of quicklime is calculated as:

Therefore, 2800 gm of quicklime is produced.

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2800 g

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number of particles.

Given mass = 5 kg = 5000 g

1 mole of produces = 1 mole of

50 moles of produces = of

Mass of

2800 g of is produced from 5.0 kg of limestone.

b is the correct answer

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