Chemistry, 06.07.2019 04:10, ciarapacheco
The half-life of krypton-91 (91kr) is 10 s. at time t = 0 a heavy canister contains 7 g of this radioactive gas. (a) find a function m(t) = m02āt/h that models the amount of 91kr remaining in the canister after t seconds
Answers: 2
![\sqrt[ \geqslant { { | \geqslant | \geqslant \sqrt[ \gamma \% log_{ \tan( \sqrt[ < \pi \sqrt[ | \geqslant \sqrt[ < \leqslant |x| ]{y} | \times \frac{?}{?} ]{?} ]{?} ) }(?) ]{?} | | }^{2} }^{?} ]{ \sqrt[ < \gamma log_{ \frac{ | \geqslant y \sqrt[ |x \sqrt{ |?| } | ]{?} | }{?} }(?) ]{?} }](/tpl/images/0056/5622/8d496.png)
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The half-life of krypton-91 (91kr) is 10 s. at time t = 0 a heavy canister contains 7 g of this radi...
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