Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2al(s)+3cl2(g)→2alcl3(s) what is the maximum mass of aluminum chloride that can be formed when reacting 15.0 g of aluminum with 20.0 g of chlorine? express your answer to three significant figures and include the appropriate units.

25.1 grams to 3 significant figures.

Explanation:

2Al(s) + 3Cl2(g) → 2AlCl3(s)

Using the molar masses:

2*26.982 g Al  reacts with 3*2*35.45 g of Cl2

53.964 g  Al reacts with 212.7 g Cl2

So 15 g Al reacts with (212.7 / 53.964)  * 15 = 59.123 g Cl2

But we only have 20 g of chlorine so the  mass of Aluminium which reacts with this is( 53.964/ 212.7) * 20

= 5.074 g.

So the maximum mass of aluminium chloride = 5.074 + 20

= 25.074 g.  (answer)

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3