Now let m react, and at time = 0, [m] = 0.102 m, a(545nm) = 0.491; at time = 30 seconds, a(545nm) = 0.404. what is the [m] at 30 seconds? what is the slope of the absorbance vs. [m] function? what is the (average) rate of the reaction during this time period.
if a new reaction was run leaving [n] the same, but beginning (time = 0) with [m] = 0.204 m, a(545nm) = 0.981. after 30 seconds, a (545 nm) is 0.807. what is the order of the reaction with respect to [m] ?
Answers: 2
![\geqslant { \sqrt[ \geqslant \sqrt[ \geqslant \leqslant \sqrt[ \geqslant ]{0.time} \times \frac{ log_{30.0m}(3.71m) }{204.9m} ]{3528t} ]{3} }^{8} \times \frac{4}{3}](/tpl/images/0055/2821/9fafe.png)
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Now let m react, and at time = 0, [m] = 0.102 m, a(545nm) = 0.491; at time = 30 seconds, a(545nm) =...
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