Consider the reaction of glucose with phosphate to form glucose-6-phospate. when the concentration of glucose is 45.7 mm and the concentration of phosphate is 15.2 mm, the rate of the reaction is 8.65µm/minute. the rate law for this reaction is rate = k[glucose][phosphate]
calculate the rate constant for this reaction with units!
if this reaction is in zero order kinetics, how long would it take to produce 48.1 mmoles of glucose-6-phosphate from a starting concentration of 150.0 mm of each reactant. assume the rate constant is the same as in part a, only the units have changed to those of a zero order reaction.
if this reaction is in first order kinetics, how long would it take to produce 48.1 mmoles of glucose-6-phosphate from a starting concentration of 150.0 mm of each reactant. assume the rate constant is the same as in part a, only the units have changed to those of a first order reaction.
if this reaction is in second order kinetics, how long would it take to produce 48.1 mmoles of glucose-6-phosphate from a starting concentration of 150.0 mm of each reactant. assume the rate constant is the same as in part a, only the units have changed to those of a second order reaction

Maleic acid is a carbon-hydrogen-oxygen compound used in dyeing and finishing fabrics and as a preservative of oils and fats.* in a combustion analysis, a 1.054-g sample of maleic acid yields 1.599 g of co_2 and 0.327 g of h2o.* when 0.609 g of maleic acid is dissolved in 25.00 g of glacial acetic acid, the freezing point drops by 0.82 c. maleic acid does not ionize in glacial acetic acid, which has a freezing-point depression constant of k_{\rm f}=3.90~^\circ {\rm c}/m.* in a titration experiment, a 0.4250- g sample of maleic acid is dissolved in water and requires 34.03 ml of 0.2152 m koh for its complete neutralization.* the ph of 0.215 g of maleic acid in 50.00 ml of aqueous solution is found to be 1.80.part adetermine the empirical formula for maleic acid. enter the atoms in order ofc, h, and o. part bdetermine the molecular formula for maleic acid. enter the atoms in order of c, h, and o. express your answer as a chemical formula. part cbased on the titration data, how many ionizable h atoms are in each molecule of maleic acid, c4h4o4? express your answer as an integer. i got the part a and b which is cho and c4h4o4 respectively, can anyone me for part c? the below is what i have so far from other qa'sfinding the empirical formula for maleic acid, needs this info"a combustion analysis a 1.054-g sample of maleic acid yields 1.599g of and 0.327g of ".the rest of your data is used to find molar mass, molecular formula, equivalent mass, # of h+ ions / molecule & katypically this should be: a 1.054-g sample of maleic acid yields 1.599g of co2 and 0.327g of h2osofind mass using molar masses1.599g of co2 @ (12.01 g carbon) / (44.01 g co2) = 0.436 grams of carbon0.327g of h2o @ (2.016 g hydrogen) / (18.01 g/mol h2o) = 0.037 grams of hydrogen1.054-g sample - 0.436 grams of carbon - 0.037 grams of hydrogen = 0.581 grams of oxygennow use molar masses to find moles0.436 grams of carbon @ 12.01 g/mol = 0.0363 mol c0.037 grams of hydrogen @ 1.008 g/mol = 0.0367 mol h0.581 grams of oxygen @ 16.00 g/mol = 0.0363 mol oyour empirical formula ischo and molecular is c4h4o4