Ethanol has a kb of 1.22 degrees c/m and usually boils at 78.4 degrees celcius. how many mol of an nonionizing solute would need to be added to 47.84 g ethanol in order to raise the boiling point to 86.30?

0.3097 moles of an nonionizing solute would need to be added.

Explanation:

Molal elevation constant =

Normal boiling point of ethanol =

Boiling of solution =

Moles of nonionizing solute = n

Mass of ethanol (solvent) = 47.84 g

Elevation boiling point:

n = 0.3097 mol

0.3097 moles of an nonionizing solute would need to be added.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.