Chemistry
Chemistry, 27.06.2019 20:20, nelyanariba981p555ve

From the entropy and enthalpy changes you found above, calculate the gibbs free energy change at 273 k. then, comment on the favorability of product formation (i. e. will the product spontaneously form? )

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Chemistry, 28.07.2019 07:00, lrich20200
Which variable is not required to calculate the gibbs free-energy change for a chemical reaction? temperature in kelvins change in entropy change in enthalpy temperature in °c?
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Chemistry, 02.08.2019 17:30, hannnahbeela
What is gibbs free energy? a) the result of the product of the temperature and entropy of a change, subtracted from the enthalpy of the change. b) the result of the product of the temperature and enthalpy of a change, subtracted from the entropy of the change. c) the result of the product of the temperature and entropy of a change, added to the enthalpy of the change. d) the result of the product of the temperature and enthalpy of a change, added to the entropy of the change.
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Physics, 10.10.2019 11:30, arielove62
The boiling point of mercury at 1 atm is 357 celsius, and the amount of heat necessary to reversibly evaporate a kilogram of mercury already at the boiling point is aq = 72780 kilogram of mercury undergoing a process of evaporation: cal. detrmine for a. a) work done by the mercury vapor against the atmosphere assuming it behaves as an ideal gas b) the change in internal energy c) the change in entropy d) the change in enthalpy e) the change in helmholtz free energy f) the change in gibbs free energy necessary data: the density of liquid mercury is 13.55 kg/l hint: you can treat the mercury vapor as an ideal gas. note that you don't need to know the equation of state of liquid mercury for this particular problem. you can calculate everything necessary with knowledge from blocks two and three.
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