Chemistry, 24.06.2019 12:10, kuehnkeegan

In which of the following is concentration expressed in percent by volume? 10% (v) 10% (m/m) 10% (m/v) 10% (v/v)

Answers: 2

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Answers

answered: fryday3111

10% (v/v).

Explanation:

V - unit is litre

m/m - by mass concentration

m/v - unit of density

v/v - concentration by volume

answered: palomaresmitchelle

Concentration expressed in percent by volume by volume is 10%(v/v).

Explanation:

w/w % or m/m% : The percentage mass or fraction of mass of the of solute present in total mass of the solution.

$w/w\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

w/v % or m/v: The percentage of mass of the of solute present in total volume of the solution.

$w/v\%=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100$

v/v % : The percentage volume of the of solute present in total volumeof the solution.

$v/v\%=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times 100$

Concentration expressed in percent by volume by volume is 10%(v/v).

answered: Guest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.