At 450 mm hg a gas has a volume of 760 l, what is its volume at standard pressure

450.0 L.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

(P₁V₁) = (P₂V₂).

V₁ = 760.0 L, P₁ = 450.0 mm Hg,

V₂ = ??? L, P₂ = 760.0 mm Hg (standard pressure = 1.0 atm = 760 mm Hg).

∴ V₂ = (P₁V₁)/(P₂) = (760.0 L)(450.0 mm Hg)/(760.0 mm Hg) = 450.0 L.

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