How much heat is released when 15.0 g of water vapor is condensed and then cooled from 100.0 c to -32.0 c? show work ❤️

46.85kJ

Explanation:

The specific latent heat of vaporization of water is =2.3 x 10⁶ J kg-1.

The specific heat capacity of water = 4.2×10³J/kgK

The latent heat of fusion of water= 3.36×10⁵ J/kg

The specific heat capacity of ice=2.108×10³ J/kgK

The heat of lost due to cooling of ice is calculated as follows by adding the heat lost during condensation of water vapor to the heat lost during cooling the water to freezing point plus the heat lost during freezing plus the heat lost during cooling the ice to -32.0°C

=MLv+MCΔT(water)+MLf+MCΔT(ice) where Lv=latent heat of vaporization of water , and Lf is the latent heat of fusion ice.

=(0.015kg×2.3 x 10⁶ J/kg)+(0.015kg×4.2×10³J/kgK×100K)+(0.015kg×3.36×10⁵ J/kg)+(0.015kg× 2.108×10³ J/kgK)×32K

=34500J+6300J+5040J+1011.84J

=46851.84J

=46.85kJ

i'm hoping this is like a multiple answer question. if it is then it would be, the location of the plants and also the height of the plants since one she wants to know where in her garden the chamomile grows best. but also to see which plants grew better in the location she also has to measure the plant itself. (if you can only choose one answer than it would be c).

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-