7.26 of a hydrate, cu(no3)2.xh2o, formed 2.4 g copper(ii) oxide. 1) what is the number of moles of cuo formed? 2) what is the number of moles of cu(no3)2.xh2o in 7.26 g? 3) what is the mass of 1 mole of cu(no3)2.xh2o? 4) mass of 1 mole of cu(no3)2 is 188g5) what is the value of x in this hydrate?

Number of moles= mass/ molar mass

Or n=m/MM

n = number of moles

m = mass

MM = molar mass

1) n CuO = 2.4g / 79.54g/mol = 0.03 mol CuO

2) n Cu(NO3)2.xH2O = 7.26 g / 205.6 = 0.035 moles of Cu(NO3)2.xH2O

3) 205.6 g

Cu = 63.5 g

N = 14g

O =16g

H= 1 g

63.5+ (14+(16*3))*2+1*2+16 =205.6 g

4) yes is 188g

5) I don’t know, I assume was 1

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8