When 2 grams of powdered lead (iv) oxide was added to 100 cm3 of hydrogen peroxide, water and oxygen were produced. lead (iv) oxide was not used up in the reaction. based on the information, which of the following is likely to decrease the rate of formation of the products? replacing the powdered lead oxide with its large crystals removing lead (iv) oxide from the reaction mixture using 50 cm3 of hydrogen peroxide using 1.0 gram of lead (iv) oxide

Replacing the powdered lead oxide with large crystals

Explanation:

The large crystals have less surface area exposed to the other reagents than the powdered  lead oxide. High surface area leads to a high rate of reaction thus the products are formed faster, while a low surface area leads to a lower rate of reaction since the reagent is less exposed to the other reagents.

odds are decent that your handwriting right now looks a little bit different than it did five years ago, and will look different again in five more. when i look back through my notebooks from middle school to now, i see a long, slow progression from meticulous and teeny letters to bigger, sloppier ones, plus a few side detours: sometime in high school, for example, i decided those loopy cursive lowercase f’s were just the coolest, adopting them as the lone rep for cursive in my otherwise all-print handwriting.

explanation:

the answer is b & c i believe : )