How many milliliters of a 1.25 molar hydrochloric acid (hcl) solution would be needed to react completely with 60.0 grams of calcium metal? (2 points) ca (s) + 2hcl (aq)yields cacl2 (aq) + h2 (g)

2400 mL

Explanation:

According to this equation, the stoichiometric ratio between and for the complete reaction is 1:2.

We know that the number of moles of can be calculated using the mole formula. (number of moles = mass / molar mass)

Moles of Calcium = = 1.5 mol

So the moles of = = 3.0 mol

Volume of HCl solution = Moles of HCl/ concentration of HCl

Volume of HCl solution = = 2400 mL

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