H2(g) + co2(g) + 10 kcal h2o(g) + co(g)

in another experiment involving the above reaction at 1,000°c, the equilibrium concentrations were found to be:

h2(g) = 2.0 moles per liter
h2o(g) = 4.0 moles per liter
co2(g) = 5.0 moles per liter
co(g) = 4.0 moles per liter

what is the equilibrium constant, keq, for this reaction?

This might be a little hard for me but I got it. So you have 2.0, 4.0, 5.0 and 4.0. Subtract from 3.0 - 2.0 = 1.0 and 4.5 - 2.0 = 2.5.

So now we have other answers. 

H20, H2, CO2 and CO

Keq reaction for each formula is 1.6

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Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

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