Consider the chemical equations shown here. 2na(s) + cl2(g) → 2nacl(s) 4na(s) + o2(g) → 2na2o(s) what is the overall equation for the reaction that produces nacl and o2 from na2o and cl2? na2o(s) + cl2(g) --> nacl(s) + o2(g) 2na2o(s) + cl2(> 2nacl(s) + o2(g) 2na2o(s) + 2cl2(> 4nacl(s) + o2(g)

2Na₂O₍s₎+ 2Cl₂₍g₎⇒4 NaCl₍s₎ +O₂₍g₎

Explanation:

The more reactive chlorine gas displaces the less reactive oxygen gas from the compound sodium oxide. The correct equation is C. because the number of each type atom on each side is equal hence the equation is balanced. There are 4 sodium atoms on the left side as there are on the right, 4 chlorine on both sides and two oxygen on both sides.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.