How many moles of calcium chloride (cacl2) are needed to react completely with 6.2 moles of silver nitrate (agno3)? 2agno3 + cacl2 → 2agcl + ca(no3)2

The no. of moles of CaCl₂ are needed = 3.1 mol.

Explanation:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂,

It is clear that 2 mol of AgNO₃ react with 1 mol of CaCl₂ to produce 2 mol of AgCl and 1 mol of Ca(NO₃)₂.

Using cross multiplication:

2 mol of AgNO₃ need  → 1 mol of CaCl₂ to react completely, from stichiometry.

6.2 mol of AgNO₃ need  → ??? mol of CaCl₂ to react completely.

∴ The no. of moles of CaCl₂ are needed = (1 mol)(6.2 mol)/(2 mol) = 3.1 mol.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

i think it's c. i'm not sure but i think so.