Fluorine-18, which has a half-life of 110 min, is used in pet scans. a. if 100. mg of fluorine-18 is shipped at 8: 00 a. m., how many milligrams of the radioisotope are still active after 110 min? b. if 100. mg of fluorine-18 is shipped at 8: 00 a. m., how many milligrams of the radioisotope are still active when the sample arrives at the radiology laboratory at 1: 30 p. m.?

Part a. 50.0 mgPart b. 12.5 mg

Explanation:

For every hal-life time the amount of the radioisotope (fluorine-18) will be cut to half.

Part a.

Since the half-life of fluorine-18 is 110 min, ater this very time, half of the fluorine-18 is still alive, i.e 100. mg / 2 = 50.0 mg. ← answer

Part b.

Compute the time elapsed from 8:00 am, when the fluorine-18 is shipped, to 1:30 pm, when the sample arrives at teh radiology laboratory.

1:30 pm - 8:00 am = 5 hours and 30 minutesConvert to minutes+ 5×60 + 30 = 330 min

Compute the number of half-lives in 330 min:

330 min / 110 min per half-life = 3 half-lives.

Conclusion:

the radiosotope has been reduced to half 3 times 100.0 mg × (1/2) × (1/2) × (1/2) = 100.0 mg × (1/2)³ = 100.0 mg / 8 = 12.5 mgHence, 12.5 mg of the radioisotope are still alive ← answer

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