Based on the data presented below, which is the strongest reducing agent? pbi2(s) + 2e– pb(s) + 2i–(aq) e° = –0.365 v ca2+(aq) + 2e– ca(s) e° = –2.868 v pt2+(aq) + 2e– pt(s) e° = 1.18 v br2(l) + 2e– 2br–(aq) e° = 1.066 v

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

yes the answer is total mass in unchanged   : )