Read the following excerpt from levitt and dubner’s freakonomics. there is a tale, “the ring of gyges,” that feldman sometimes tells his economist friends. it comes from plato’s republic. a student named glaucon offered the story in response to a lesson by socrates—who, like adam smith, argued that people are generally good even without enforcement. glaucon, like feldman’s economist friends, disagreed. he told of a shepherd named gyges who stumbled upon a secret cavern with a corpse inside that wore a ring. when gyges put on the ring, he found that it made him invisible. with no one able to monitor his behavior, gyges proceeded to do woeful things—seduce the queen, murder the king, and so on. glaucon’s story posed a moral question: could any man resist the temptation of evil if he knew his acts could not be witnessed? glaucon seemed to think the answer was no. the excerpt serves as which of the following in relation to the authors’ argument? a claim that most people are moral an example of morality in the workplace a conclusion about morality in the workplace a counterclaim to the idea that most people are moral

Outermost (valence) electrons

Dumb kids playing chess on freeways go spat domain

1) according to the law of conservation of mass ,in all chemical reactions total mass is unchanged

Note that 2 mol dm⁻³ = 2 mol/(dm³)outline: we're given the concentration of hcl, which is  2 mol dm⁻³ (cubic meters in the denominator can represent volume, so i know this is concentration). we're an amount of calcium carbonate caco₃, which is 5 g. we're presented with a chemical equation which includes caco₃ and hcl. we are told to find the volume of hcl. from what we see so far, this seems to be a stoichiometry  problem. we'll have to use the given information about calcium carbonate to find the amount of moles of hcl needed to fully react with calcium carbonate. then we'll have information about the moles of hcl and the concentration of hcl; that will be enough to figure out volume according to the formula concentration = moles / volume.======all the answer choices are not in dm.convert the given concentration so that it uses cm⁻³.we can use conversion factors. we have to cube our conversion factors so that dimensional analysis works.we can convert to meters first, using the fact that     10 dm = 1 m  ⇔ 10³ dm³ = 1 m³then we use the fact that     10² cm = 1 m ⇔ (10² cm)³ = (1 m)³ ⇔ 10⁶ cm³ = 1 m³so converting:     now we have to find the moles of hydrochloric  acid neededfind the moles of calcium carbonate. we have to find the molar mass of calcium carbonate, caco₃, which can be found by    molar mass = (mass ca) + (mass c) + 3(mass o)    = 40 + 12 + 3(16)    = 100 g/molconvert the given 5 g to moles:     mol caco₃ = 5 g caco₃ * 1 mol/(100 g) = 0.05 mol caco₃use stoichiometry (ratios) to figure out the moles of hcl needed. ratio wise, there's 2 hcls for every caco₃, so use dimensional analysis    mol hcl = mol caco₃ * (2 mol hcl) / (1 mol caco₃)    = 0.05 mol hcl * 2    = 0.1 mol hcl  we have 0.1 mol hcl and concentration of hcl (0.002 mol/cm³).we need to find volumesince concentration = moles / volume, rearrange to get     volume = moles / concentration    volume = 0.1 mol / (0.002 mol/cm³)    volume = 50 cm³