What is the oxidation state of nitrogen in nano2

Therefore, the oxidation state of N in NaNO₂ is +3

Explanation:

Problem: calculating the oxidation state of nitrogen N in NaNO₂

let us denote the oxidation number of Nitrogen as N:

We know from the periodic table that Na has an oxidation number of +1 i.e it will readily want to lose 1 electron so as to complete its octet.

Oxygen is known to have an oxidation number of -2

Summation of the oxidation number of each atoms is 0 for neutral compound.

Therefore to calculate the oxidation state of Nitrogen in NaNO₂, we express as:

                              +1 + N + (-2 x 2) = 0

                                1 + N = 4

                                 N = 4-1 = +3

Therefore, the oxidation state of N in NaNO₂ is +3

that's what i got you can count the number of atoms