In an acid-base neutralization reaction 38.74 ml of 0.500 m potassium hydroxide reacts with 50.00 ml of sulfuric acid solution. what is the concentration of the h2so4 solution?

0.2 M.

Explanation:

The no. of millimoles of acid is equal to that of the base at the neutralization.

∴ (XMV) KOH = (XMV) H₂SO₄.

X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),

M is the molarity.

V is the volume.

X = 1, M = 0.5 M, V = 38.74 mL.

X = 2, M = ??? M, V = 50.0 mL.

∴ M of H₂SO₄ = (XMV) KOH/(XV) H₂SO₄ = (1)(0.5 M)(38.74 mL)/(2)(50.0 mL) = 0.1937 M ≅ 0.2 M.

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

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