Achemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. the vessel is a stainless-steel cylinder that measures 17.0cm wide and 20.4cm high. the maximum safe pressure inside the vessel has been measured to be 2.20mpa. for a certain reaction the vessel may contain up to 0.0985kg of boron trifluoride gas. calculate the maximum safe operating temperature the engineer should recommend for this reaction. write your answer in degrees celsius. round your answer to significant digits.

The reaction is to performed in the cylindrical vessel. The volume of the cylindrical vessel for performing the reaction will be:

Volume of cylinder = h

For calculating the maximum temperature of the reaction, ideal gas equation is used.

PV = nRT

where, P = pressure

Therefore, the temperature of the system will be .

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Explanation:

1) Data:

a) Cylinder diameter: d = 17.0 cm

b) Cylinder height: H = 20.4 cm

c) p = 2.20 MPa

d) compound: BF₃ gas

e) mass, m = 0.0985 kg

2) Formulae:

a) Volume of a cylinder, V = π r² H

b) Number of moles, n = mass in grams / molar mass

c) Ideal gas equation: pV = nRT

3) Solution:

a) Volume (V)

i) r = d / 2 = 17.0 cm / 2 = 8.50 cm

ii) V = V = π r² H = π (8.50 cm) ² (20.4 cm) = 4,630 cm³ = 4.630 liter

b) Number of moles (n)

i) molar mass BF₃: 67.82 g/mol

ii) n = mass in grams / molar mass = 98.5 g / 67.82 g/mol = 1.452 mol

c) Temperature

i) pressure conversion: 2.20 MPa = 22.21 atm

ii) pV = nRT ⇒ T = pV / (nR)

The result is given with 3 significant figures, since that is the number of significant figures used for the data.

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol