2s(s) + 3 o2(g) → 2 so3(g) δh°rxn = ? given: so2(g) → s(s) + o2(g) δh°rxn = +296.8 kj 2 so2(g) + o2(g) → 2 so3(g) δh°rxn = -197.8 kj use the standard reaction enthalpies given below to determine δh°rxn for the following reaction: 2 s(s) + 3 o2(g) → 2 so3(g) δh°rxn = ? given: so2(g) → s(s) + o2(g) δh°rxn = +296.8 kj 2 so2(g) + o2(g) → 2 so3(g) δh°rxn = -197.8 kj -293.0 kj -692.4 kj -494.6 kj 1583 kj -791.4 kj

its first and third is your answer i did the qustion the fourth isnt right

2b2t

explanation:

2b2t

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o