In the lab, a chemist adds 3.6 grams of sodium chloride to 100.0 g of water. what is the molality of the solution?

0.616 m.

Explanation:

m = (no. of moles of solute)/(mass of the solvent (kg))

m = (mass/molar mass) NaCl / (mass of the solvent (kg))

mass of NaCl = 3.6 g, molar mass of NaCl = 58.44 g/mol, mass of water = 100.0 g = 0.1 kg.

m = (mass/molar mass) NaCl / (mass of the solvent (kg)) = (3.6 g / 58.44 g/mol) / (0.1 kg) = 0.616 m.

answer by yourhope:

how do models compare to real-world objects?

d. most models represent a real-world object in a simpler way.

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