How many liters of 0.200 m sodium hydroxide do you need to titrate 0.400 l of a 0.100 m diprotic acid to the equivalence point? 0.400 l naoh

Explanation:

Since, the acid is diprotic, you have that 1 mol of it releases 2 mol of hydrogen ions, H⁺.

Determine the number of moles of acid, using the molarity definition:

And the number of moles of H⁺ ions equals 2 × 0.0400 mol = 0.0800 mol

At the equivalence point of the titration the number of moles of H⁺ from the acid equals the number of moles of OH⁻ from the base.

Since, sodium hydroxide ionizes in a ratio 1 : 1 (1 mol of NaOH / 1 mol OH⁻), the number of moles of NaOH is equal to 0.0800 mol

And now you use the molarity definition for the 0.200 M sodium hydroxide solution:

That is the 0.400 liter of 0.200 M sodium hydroxide.

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

it would be a gas formation