The specific gravity of iron is 7.87, and the density of water at 4.00 ∘c is 1.00 g/cm3. you can use this information to find the density of iron.
find the volume occupied by 7.00 g of iron.

Solution:

Density of iron( d)=?

Specific gravity of iron=7.87

Density of water at 4°C=1g/cm^3

we have,

specific gravity =density of object/density of water at 4°C

or,7.87=d/1

or, d=7.87g/cm^3

Again,

density=mass/ volume

or,7.87=7/V

or,V=7/7.87

or,V=0.88cm^3

therefore, volume occupied by iron is 0.88cm^3

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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