What is the concentration of an naoh solution that requires 50 ml of a 1.25 m h2so4 solution to neutralize 78.0 ml of naoh

Explanation:

The most common way to solve this kind of problem is to use the formula  

In your problem,

For NaOH

C₁ =??     v₁= 78.0 mL = 0.078 L

For H₂SO₄

C₁ =1.25 M     v₁= 50.0 mL = 0.05 L

but you must note that for the reaction of NaOH with H₂SO₄

2 mol of NaOH raect with 1 mol H₂SO₄

So, by applying in above formula

So, the answer is the concentration of an NaOH = 1.6 M

it would be a gas formation