Chemistry
Chemistry, 29.09.2019 07:20, Itslegit3

Al(s0 + hcl (aq) > alcl3(aq) + h2(g) what are the products in this reaction?

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Chemistry, 24.06.2019 15:00, ray109
The following data was collected when a reaction was performed experimentally in the laboratory. reaction data reactants products al(no3)3 nacl nano3 alcl3 4 moles 9 moles ? ? determine the maximum amount of alcl3 that was produced during the experiment. explain how you determined this amount.
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Chemistry, 24.06.2019 16:30, bella2017
The following data was collected when a reaction was performed experimentally in the laboratory. reaction data reactants products al(no3)3 nacl nano3 alcl3 starting amount in reaction 4 moles 9 moles determine the maximum amount of alcl3 that was produced during the experiment. explain how you determined this amount.
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Chemistry, 29.06.2019 16:30, 12290737
Which of the following is a correct balanced equation for the neutralization reaction that occurs between al(oh)3 and hcl (aq)? a. al(oh)3 + 3 hcl (aq) ô alcl3 + h+ + oh b. al3+ + oh- + h+ + cl- ô alcl3 + h2o c. al(oh)3 + hcl (aq) ô alcl3 + h2o d. al(oh)3 + 3 hcl (aq) ô alcl3 + 3 h2o
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Chemistry, 16.10.2019 16:10, kirstenb278
What is δhf° for alcl3(s)? given: 2al(s) + 3 cl2(g) → 2 alcl3(s) δh°rxn = - 706 kj a) 109 kj/mol b) 218 kj/mol c) -353 kj/mol d) -706 kj/mol e) -218 kj/mol *i think it’s c cause the standard enthalpies of formation for al and cl2 = 0 and δh°rxn = products - reactants. so, (2mol x δh°f alcl3(s)) - [(2mol x 0kj/mol) + (3mol x 0kj/mol)] = -706 kj 2mol x δh°f alcl3(s) = -706kj δh°f alcl3(s) = -353kj/mol, right? but when i googled the standard enthalpy of formation for alcl3(s), the table said it was about -704kj/mol, which means d is correct?
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Al(s0 + hcl (aq) > alcl3(aq) + h2(g) what are the products in this reaction?...

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