Solve using the correct gas law formula: if the pressure exerted by gas at 25 °c in a constant volume of 3.81 atm, what will the pressure be at 50 °c?

4.31 atm.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

(P₁T₂) = (P₂T₁)

P₁ = 3.81 atm, T₁ = 25°C + 273 = 298 K,

P₂ = ??? atm, T₂ = 50°C + 273 = 323 K,

(P₁T₂) = (P₂T₁)

∴ P₂ = (P₁T₂)/(T₁) = (3.81 atm)(323 K)/(298 K) = 4.31 atm.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml