3.00 moles of helium gas (he) are in a container with a volume is 2.00 liters and a temperature is at 298 k. what is the approximate pressure in kilopascals?

3718.628 kPa.

Explanation:

where, P is the pressure of the gas in atm (P = ??? atm).

V is the volume of the gas in L (V = 2.0 L).

n is the no. of moles of the gas in mol (n = 3.0 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 298.0 K).

∴ P = nRT/V = (3.0 mol)(0.0821 L.atm/mol.K)(298.0 K)/(2.0 L) = 36.7 atm.

∵ 1.0 atm = 101.325 kPa.

∴ P = (36.7 atm)(101.325 kPa/1.0 atm) = 3718.628 kPa.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.

mol/g

explanation:

i had a similar question and i got it right so i think this one is right.