A4,000 ml solution of agno3 contains 17.00 g of solute in water. calculate the molarity (molar concentration) of the solution.
3 x 10 -5m
3 x 10 -2m
4 x 10 -1m
1 x 10 -4m

2.5 x 10⁻² ≅ 3.0 x 10⁻² M.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (mass/molar mass)of AgNO₃/(V of the solution (L)).

∴ M of AgNO₃ = (17.0 g / 169.87 g/mol)/(4.0 L) = 2.5 x 10⁻² ≅ 3.0 x 10⁻² M.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

where,

n= moles of solute

= volume of solution in ml

moles of solute =

Now put all the given values in the formula of molarity, we get

Thus molarity of the solution will be

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each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i