Zn(s) + 2hcl(aq) → zncl2(aq) + h2(g) if you have 4 moles of zinc and 4 moles of hydrochloric acid, which of these would be the limiting reactant? a) zinc b) hydrogen gas c) zinc chloride d) hydrochloric acid

D) hydrochloric acid.

Explanation:

Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g),

It is clear that 1.0 moles of Zn react with 2.0 moles of HCl to produce 1.0 moles of ZnCl₂ and 1.0 mole of H₂.

∴ 2.0 mol of Zn (the remaining 2.0 mol is in excess) react completely with 4.0 mol of HCl with (1: 2) molar ratio.

So,

the limiting reactant is HCl and the excess reactant is Zn.

Thus, the right choice is: D) hydrochloric acid.

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