Consider the following reaction: h2(g)+i2(g)⇌2hi(g) complete the following table. assume that all concentrations are equilibrium concentrations in m. t(∘c) [h2] [i2] [hi] [kc] 25 0.0355 0.0388 0.922 − 340 − 4.60×10−2m 0.394m 9.6 445 4.90×10−2m 4.76×10−2m − 50.2 find kc at 25∘c. find [h2] at 340∘c. find [hi] at 445∘c.

These are three questions.

Explanation:

I will start by copying the table for better understanding of the data and the work to do.

T(∘C)       [H2]                    [I2]                     [HI]               [Kc]

25           0.0355               0.0388              0.922            -

340                                    4.60×10⁻²M       0.394M         9.6

445         4.90×10−2M      4.76×10⁻²M           −                50.2

The chemical equation that represents the equilibrium is also given:

From that equilibrium equation, you can fnd the expression of the equlibrium constant, Kc, as:

The calculations and explanations to answer the three questions are in the pdf file attached.

Please, click on the image of the file to open it.

since electrons are negative the answer is neagtaive

gas

explanation:

smoke is the matter of a gas