How many grams of ammonium chloride (nh4cl) do you have if you have 0.436 moles?

0.436 moles of ammonium chloride (NH4Cl) has a mass of 23.3 grams

Explanation:

Step 1: Data given

Number of moles of NH4Cl = 0.436 moles

Molar mass of NH4Cl = 53.49 g/mol

Step 2: Calculate mass of ammonium chloride

Mass = moles * molar mass

Mass NH4Cl = moles NH4Cl * molar mass NH4Cl

Mass NH4Cl = 0.436 moles * 53.49 g/mol

Mass NH4Cl = 23.3 grams

0.436 moles of ammonium chloride (NH4Cl) has a mass of 23.3 grams

the answer is 1 i believe

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2