Ascuba diver 25.0m below the sea surface inhales 75.0ml of compressed air in a scuba tank at a pressure of 3.50atm and a temperature of 5.0c. what is the pressure of the air in the lungs if the gas expands to 215.0ml at the body temperature of 37.2c?

Explanation:

Use the combined gas law

P(V)/T=P(V)/T

P is pressure

V is volume

T is temperature

3.5 atm(75 mL)/(5 C)=P(215 mL)=(37.2 C)

yu can change celcius to kelvin by adding 273.

And then just solve the equation

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.