Ihave 0.725 liters of a 1.500m solution of cacl2. how many grams of cacl2 are in the solution

120.7 g.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (mass/molar mass)of NaCl/(V of the solution (L)).

∴ mass of CaCl₂ = (M)(V of the solution (L))(molar mass) = (1.5 M)(0.725 L)(110.98 g/mol) = 120.7 g.