If you needed to make 100 ml of a 0.2 m fruit drink solution from the 1.0 m fruit drink solution, how would you do it? (hint: use msvs = mdvd to find the amount of concentrated solution you need, then add water to reach 100 ml.) show your work.

We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.

Explanation:

According to the neutralization law,

where,

= molarity of stock solution = 0.2 M

= volume of stock solution = 100 ml

= molarity of resulting solution = 1.0 M

= volume of resulting solution = ?

Now put all the given values in the above law, we get the volume of resulting solution.

Therefore, the volume of 1.0 M required is 20 ml.

We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer