Calorimetry can be used to find heats of combustion. suppose a calorimeter someone to determine that 4032 kj of heat is released during the combustion of 88.0 grams of propane, c3h8 (44.0 g/mol). what would be the amount of heat released for the combustion of 0.500 moles of propane?

1008.0 kJ.

Explanation:

n = mass/molar mass = (88.0 g)(/(44.0 g/mol) = 2.0 mol.

∴ The combustion of 2.0 moles of propane produces 4032.0 kJ.

Using cross multiplication:

The combustion of 2.0 moles of propane produces → 4032.0 kJ.

The combustion of 0.5 moles of propane produces → ??? kJ.

∴ The amount of heat released for the combustion of 0.5 moles of propane = (4032.0 kJ)(0.5 mol)/(2.0 mol) = 1008.0 kJ.

i know insulin is primary but i dont know the others im sorry

explanation:

c. orbital shape i hope this is correct