Asaline solution contains 1.1% nacl by mass. how much nacl is present in 96.3 g of this solution

= 1.0593 g

Explanation:

1.1% NaCl by mass, means;

1.1 g per 100 g = 0.011

Therefore; the amount of NaCl present in 93.6 g of the solution is;

= 0.011 × 96.3 g

= 1.0593 g

im pretty sure its b

може ли да зареждате повече информация, моля