Determine the celsius temperature of 2.49 mol of gas contained in a 1.00 l vessel

= -266.24°C

Explanation:

According to ideal gas law;

PV = nRT, where P is pressure, V is the volume, n is the number of moles, R is the ideal gas constant and T is the temperature.

PV = nRT  

T = PV/(nR)

   = 143 kPa * (1atm/101.325 kPa) * 1.00L / (2.49 mol * 0.08206 Latm/molK)

    = 6.91 K

     = -266.24°C

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.

pie chart because it is in percents ( % )