Suppose that 25 g of each substance is initially at 27.0 °c. what is the final temperature of each substance upon absorbing 2.35 kj of heat?

a. gold

b. silver

The final temperature of the gold when it absorbs the heat is 755.68 ⁰C.

The  final temperature of the silver when it absorbs the heat is 418.67  ⁰C.

The given parameters;

The final temperature of the gold when it absorbs 2,350 J;

Q = mcΔt

The final temperature of the silver when it absorbs 2,350 J;

Q = mcΔt

Learn more here:link

a. gold : 755.7°C.

b. silver: 418.7°C.

Explanation:

a. gold :

The amount of heat absorbed by gold = Q = m.c.ΔT.

where, m is the mass of Au (m = 25.0 g).

c is the specific heat capacity of Au = 0.129 J/g°C.

ΔT is the temperature difference = (final T - 27.0°C).

Q = 2.35 kJ = 2350.0 J.

∴ The amount of heat absorbed by Au = Q = m.c.ΔT = 2350.0 J.

∴ 2350.0 J = (25.0 g)(0.129 J/g°C)(final T - 27.0°C).

∴ 2350.0 J = 3.225 final T - 87.08.

∴ 3.225 final T = 2350.0 + 87.08 = 2473.

∴ final T = 2473/3.225 = 755.7°C.

b. silver:

The amount of heat absorbed by silver = Q = m.c.ΔT.

where, m is the mass of Ag (m = 25.0 g).

c is the specific heat capacity of Ag = 0.24 J/g°C.

ΔT is the temperature difference = (final T - 27.0°C).

Q = 2.35 kJ = 2350.0 J.

∴ The amount of heat absorbed by Ag = Q = m.c.ΔT = 2350.0 J.

∴ 2350.0 J = (25.0 g)(0.24 J/g°C)(final T - 27.0°C).

∴ 2350.0 J = 6.0 final T - 162.0.

∴ 6.0 final T = 2350.0 + 162.0 = 2512.

∴ final T = 2512/6.0 = 418.7°C.

14 days is the half-life of phosphorus-32

personal, she chose to do it.