An aqueous solution at 25°c has a oh− concentration of 1.9x10−8m . calculate the h3o+ concentration. be sure your answer has the correct number of significant digits.

= 5.26 × 10^-7 M

Explanation:

We know that;

[H3O+][OH-] = 1 x 10^-14

Therefore;

Given; OH− concentration = 1.9x10^−8 M

Then; [H3O+] = (1 x 10^-14)/[OH-]

                      = (1 x 10^-14)/(1.9x10^−8)

                      = 5.26 × 10^-7 M

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