Thermodynamic properties
property value
c (solid) 0.5 j/g °c
c (liquid) 1.0 j/g °c
c (gas) 2.0 j/g °c
melting point −114 °c
boiling point 78 °c

how much heat is released when 60.0 g of ethanol cools from 70 °c to 43 °c?

1,620 J.

Explanation:

Q = m.c.ΔT.

where, Q is the amount of heat released from ethanol cooling,

m is the mass of ethanol (m = 60.0 g),

c is the specific heat of ethanol in the liquid phase, since the T is cooled below the boiling point and above the melting point (c = 1.0 J/g °C),

ΔT is the temperature difference (final T - initial T) (ΔT = 43.0 °C – 70.0 °C = - 27.0 °C).

∴ Q = m.c.ΔT = (60.0 g)(1.0 J/g °C)(- 27.0 °C) = - 1620 J.

*tilts head* sounds more like a statement

14,16 18 reacts with group