Determine the molar mass of a 0.458 gram sample of gas having a volume of 1.20 l at 287 k and 0.980 atm. show work.
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9.165 g/mol.

Explanation:

PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the container in L.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas in K.

∵ n = mass/molar mass.

∴ PV = (mass/molar mass)RT

∴ molar mass = (mass/PV)*(RT)

∵ m = 0.458 g, R = 0.082 L.atm/mol.K, P = 0.98 atm, V = 1.20 L, T = 287 K.

∴ molar mass = (mass/PV)*(RT) = (0.458 g/(0.98 atm)(1.20 L))*(0.082 L.atm/mol.K)(287 K) = 9.165 g/mol.

organisms are more likely to be more preserved in mud than sand because mud is moist and wet, while sand is very dry.

answer : a model is often used to explain and make things easier to understand when any scientific topic needs to be demonstrated and explained.

as in this case where a scientist wants to use a model to present the results of his detailed scientific investigation. he should do it as it will him to make the audience understand the concept in a much better way. also, it can be changed according to new scientific understandings.