Chemistry
Chemistry, 06.10.2019 13:30, mhayslett

Bromination of (z)? 3? hexene yields racemic 3,4? dibromohexane. provide a detailed mechanism for formation of the (3s,4s)? enantiomer, specifically showing br2 addition occurring from the top face of the alkene.

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Chemistry, 05.09.2019 16:20, rafa3997
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Chemistry, 07.11.2019 00:31, sajdshjad751
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Chemistry, 14.11.2019 01:31, tyturbo7
The products obtained by adding 1 mole of hbr to 2,4-hexadiene area. 4-bromo-2-hexene and 5-bromo-2-hexene.b. 3-bromo-2-hexene and 4-bromo-2-hexene.c. 4-bromo-2-hexene and 2-bromo-4-hexene.d. 2-bromo-3-hexene and 3-bromo-2-hexene.e. 2-bromo-3-hexene and 4-bromo-2-hexene.
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Chemistry, 16.11.2019 02:31, ammarsico19
Compound w, c8h17br, and x, c8h17cl, are products of the radical bromination (w), and chlorination (x), of 2,4-dimethylhexane. w and x are each chiral. w reacts readily in water to form a chiral substitution product y, c8h17oh. reaction of a single enantiomer of w produces a single enantiomer of y as the only substitution product. x likewise reacts readily in water though at a slower rate than w; a chiral substitution product z, c8h17oh, is again formed. unlike w, however, reaction of a single enantiomer of x produces z that is nearly racemic. propose structures for w and x.
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