Me!

a total of 25.0 ml of 0.150 m potassium hydroxide (koh) was required to neutralize 15.0 ml of sulfuric acid (h2so4) of unknown concentration. what is the concentration of the sulfuric acid? pls fill out the table a million!

The neutralization reaction is expressed as:

2KOH + H2SO4 = K2SO4 + 2H2O

We are given the volume and the concentration of the KOH that is used in the reaction. We use this and the relations from the reaction to determine the concentration of the acid.

0.150 mol KOH / L ( .025 L ) ( 1 mol H2SO4 / 2 mol KOH ) = 0.00188 mol H2SO4

Concentration of acid = 0.00188 mol / .015 = 0.125 M of sulfuric acid

hey Hanna .  

do you remember me?

im turkish

I guess you lived in western karolina

Was your name hanna or allecia or alex?

have your rabbits grown?

Explanation:

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation: