Asample of a compound contains 32.0 g c and 8.0 g h. its molar mass is 30.0 g/mol. what is the compound’s molecular formula?

The answer is: C2H6

First, we need to find the empirical formula of the compound:

Looking for the relative atomic mass for each element:

Finding the number of moles for each element:

Then, we need to determinate the mole ratio by dividing each result into the smallest number:

So, the empirical formula would be CH3

We are given the molar mass of the compound is equal to 30 g/mol

We need to compare the empirical formula molecular mass and the molecular formula molar mass in order to find the number of atoms of the compound:

Empirical formula molar mass:

Molecular formula molar mass = 30.0 g/mol

So, by dividing the molecular formula molar mass by the empirical formula molar mass we have the number of atoms of the compound:

Therefore,

The molecular formula will be: (CH3)2= C2H6

Have a nice day!

it's c. elements are placed in rows based on how may valencies electrons have.

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