How many grams of fe2o3 will be produced from 37.5 grams of iron

Step 1 : Convert mass of Iron to moles using n = m/MM.

n(Fe) = 37.5 ÷ 55.845 = 0.671501... mol

Step 2 : Using stoichiometric ratios, find how many moles of Fe2O3 are produced.

Fe : Fe2O3 is 4:2, or simply 2:1. For every 2 moles of Fe there is Fe2O3.

Therefore, moles of Fe2O3 is half the amount of Fe!

n(Fe2O3) = 0.5 x 0.671501... = 0.33575... mol

Step 3: Convert the moles of Fe2CO3 to mass using m = n x MM.

m(Fe2O3) = 0.33575... x [2(55.845)+3(15.999)] = 53.61502... grams

Final step: round your answer to the lowest signficant figures. Since you gave me the mass of iron to 3s.f, m(Fe2O3) = 53.6 grams (3s.f) !

Let me know if you're confused in any way!

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